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3-8 Calculating Friction Loss In Hose LaysFriction Loss Formulas and Calculations FL = (C x Q2)(L) Friction Loss Formula FL = (C x Q2)(L) C = Coefficient for hose diameter Q = Quantity L = Length FL Coefficients C factors refer to the third principle of friction loss The base of the friction loss equation Assigned based on the diameter of the hose FL decreases as diameter increases Reflects a worst-case scenario Results are probably slightly higher Standard (Coefficients) 1"=150 1½"=24 1¾"=10 2½"=2 3"=0.8 4"=0.2 4½"=0.1 5"=0.08 Calculating "Q" Q = 200 (gpm)/100 Q = 2 If gpm is 400, what is Q? Q = 400 (gpm)/100 Q = 4 Second step of formula Must be calculated, then applied If gpm is 200, what is Q? FL = (2 x 22)(1) FL = (2 x 4)(1) FL = (8)(1) FL = 8 psi 200 gp m 100' of 2½" Calculating FL FL = (2 x 12)(3) FL = (2 x 1)(3) FL = (1)(3) FL = 6 psi 100 gp m 300' of 2½" Calculating Single Hose FL Multiple Hoselines -Equal Size/Length Calculate FL for one hoseline only if other hoselines will have the same pressure and gpm 1" at 50 psi 400' of 2½"Calculate Q gpm = (29.7)(d2 x NP) gpm = (29.7)(12 x 50) gpm = (29.7)(1 x 7.0711) gpm = (29.7)(7.0711) gpm = 210 psi = 200 psi Q = 200/100 = 2 1" nozzles 400'of 2½"Calculate FL FL = (C x Q2)(L) FL = (2 x 22)(4) FL = (2 x 4)(4) FL = (8)(4) FL = 32 psi Wyed Hoselines -Equal Lengths One hoseline supplies two others Two 1½" or 1¾" attack lines wyed from a 2½" supply line is common Calculate FL for supply line and one wyed hoseline, then add together Only one needs to be computed since they carry equal amounts of water Wye Line Q = 150 100 Q = 1.5 2½" Line Q = 300 100 Q = 3 Calculate Q 200' of 2½" 150 gpm 150' of 1¾" Calculate FL 200' of 2½" 150 gpm 150' of 1¾" 2½" Line FL = (C x Q2)(L) FL = (2 x 32)(2) FL = (2 x 9)(2) FL = (18)(2) FL = 36 psi 34 psi 36 psi 70 psi Wye Line FL = (C x Q2)(L) FL = (10 x 1.52)(1.5) FL = (10 x 2.25)(1.5) FL = (22.5)(1.5) FL = 34 psi Siamese Hoselines -Equal Length Two or more parallel hoselines Divide gpm by total number of hoselines Then calculate FL for one line Take ½ of the gpm flow and figure the FL for one line Coefficients are used in calculating FL 2½" Line Q = 300 100 Q = 3 Siamese Q = 150 100 Q = 1.5 1,000' of 3" 300 gpm 1,000' of 3" 300' of 2½" Calculate Q 1,000' of 3" 300 gpm 1,000' of 3" 300' of 2½" Calculate FL 2½" Line FL = (C x Q2)(L) FL = (2 x 32)(3) FL = (2 x 9)(3) FL = (18)(3) FL = 54 psi Siamese FL = (C x Q2)(L) FL = (.8 x 1.52)(10) FL = (.8 x 2.25)(10) FL = (1.8)(10) FL = 18 psi 1,000' of 3" 300 gpm 1,000' of 3" 300' of 2½" Calculate FL Add FL together 54 psi 18 psi 72 psi Multiple Hoselines -Unequal Length Calculate FL for each line Pump for highest pressure needed Gate down discharge of line(s) needing less pressure Calculating Q Q = 250 100 Q = 2.5 250 gpm 300' of 2½" 500' of 2½" 250 gpm Line 1: 300' of 2½" Line 2: 500' of 2½" Calculate FL Line 2 FL = (C x Q2)(L) FL = (2 x 2.52)(5) FL = (2 x 6.25)(5) FL = (12.5)(5) FL = 63 psi Line 1 FL = (C x Q2)(L) FL = (2 x 2.52)(3) FL = (2 x 6.25)(3) FL = (12.5)(3) FL = 38 psi 63 psi Wyed Hoselines -Unequal Length Addition of hose lengths to an existing wyed hoseline assembly may result in unequal length attack lines Calculate FL for supply line and both wyed hoselines Pump to the highest wyed line and gate-down the other wyed line Calculate Q 200' of 2½" 100 gpm 200' of 1½" 150' of 1½" Wye Line Q = 100 100 Q = 1 2½" Line Q = 200 100 Q = 2 Calculate FL 150' Wye Line FL = (C x Q2)(L) FL = (24 x 12)(1.5) FL = (24 x 1)(1.5) FL = (24)(1.5) FL = 36 psi 2½" Line FL = (C x Q2)(L) FL = (2 x 22)(2) FL = (2 x 4)(2) FL = (8)(2) FL = 16 psi 200' of 2½" 100 gpm 200' of 1½" 150' of 1½" 200' Wye Line FL = (C x Q2)(L) FL = (24 x 12)(2) FL = (24 x 1)(2) FL = (24)(2) FL = 48 psi Calculate FL 48 psi 16 psi 63 psi 200' of 2½" 100 gpm 200' of 1½" 150' of 1½" October 2008 Slide 3-8-26 Siamese Hoselines -Unequal Length Add the lengths of each line together, then divide by total number of lines 2½" Line Q = 250 100 Q = 2.5 Siamese Q = 125 100 Q = 1.25 900 of 3" 250 gpm 1,000' of 3" 100' of 2½" Calculate Q 900 of 3" 250 gpm 1,000' of 3" 100' of 2½" Calculate FL Determine L 900 1,000 1,950 1,950 2 = 950 950 100 = 9.5 Siamese FL = (C x Q2)(L) FL = (.8 x 1.252)(9.5) FL = (.8 x 1.56)(9.5) FL = (1.25)(9.5) FL = 12 psi 900 of 3" 250 gpm 1,000' of 3" 100' of 2½" Calculate FL 2½" Line FL = (C x Q2)(L) FL = (2 x 2.52)(1) FL = (2 x 6.25)(1) FL = (12.5)(1) FL = 13 psi 13 psi 12 psi 25 psi